Question

A +0.0129 C charge feels a 4110 N

force from a -0.00707 C charge. How
far apart are they?
[?] m

Answer 1

14.13 m

Step-by-step explanation:

acellus

Answer 2

r = 14.13 m

Step-by-step explanation:

Given that,

Charge 1, q₁ = +0.0129 C

Charge 2, q₂ = -0.00707 C

The force between charges, F = 4110 N

We need to find the distance between charges. The formula for the force between charges is given by :

`F=k(q_1q_2)/(r^2)`

Where

r is the distance between charges

So,

`r=\sqrt{(kq_1q_2)/(F)} \\\\r=\sqrt{(9* 10^9* 0.0129 * 0.00707 )/(4110 )} \\\\r=14.13\ m`

So, the distance between charges is equal to 14.13 m.