Question

How many particles of ZnCrO4 are present in a 4.5 mole sample?

Answer 1

2.7 × 10²⁴ particles ZnCrO₄

General Formulas and Concepts:

Chemistry

Atomic Structure

• Moles
• Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

• Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

[Given] 4.5 mol ZnCrO₄

[Solve] particles ZnCrO₄

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

1. [DA] Set up:
   `\displaystyle 4.5 \ mol \ ZnCrO_4((6.022 \cdot 10^(23) \ particles \ ZnCrO_4)/(1 \ mol \ ZnCrO_4))`
2. [DA] Multiply [Cancel out units]:
   `\displaystyle 2.7099 \cdot 10^(24) \ particles \ ZnCrO_4`

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

2.7099 × 10²⁴ particles ZnCrO₄ ≈ 2.7 × 10²⁴ particles ZnCrO₄