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Hi can someone please help me with this question I've been stuck on it for soooo long!!

Hi can someone please help me with this question I've been stuck on it for soooo long-example-1
User Vyacheslav
by
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1 Answer

2 votes

Answer:

Let x=sinθ

2sin²θ = 5sinθ - 3

2x²=5x-3

2x²-5x+3=0

(2x-3)(x-1)=0

2x-3=0 or x-1=0

x=3/2 or x=1

sinθ=2/3 or sinθ=1

θ=arcsin(2/3) or θ=arcsin(1)

θ=0.729727656 or θ=1.57079633=π/2

User Neli
by
8.3k points
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