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A pumpkin is thrown horizontally off of a building at a speed of 2.5 — and travels a horizontal distance of

12 m before hitting the ground. We can ignore air resistance.

What is the vertical velocity when it hits the ground

User Nbonbon
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2 Answers

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A pumpkin is thrown horizontally off of a building at a speed of 2.5 m/s and travels a horizontal distance of 12 m before hitting the ground. We can ignore air resistance.

What is the pumpkin's vertical velocity when it hits the ground?

Answer: -47.04

User Sultan Shakir
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4 votes

Answer:

Step-by-step explanation:

This is a missile throwing exercise, let's find the distance

x = v₀ₓ / t

t = v₀ₓ / x

let's calculate

t = 2.5 / 12

t = 0.2083 s

as time is a scalar this is the same value for descends to the ground

y = v_{oy} t - 1/2 g t²

we calculate

v_y = 0 - 9.8 0,2083

v_y = - 2.04 m / s

the negative sign indicates that the speed is down

User Dan Dye
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