Question

A student in the lab accidentally poured 45 mL of water into a graduated cylinder containing 15 mL of 3.0 M HCL. What is the concentration of the new solution?

Answer 1

The correct approach is "1 M".

Step-by-step explanation:

The given values are:

Volume of HCL,

V₁ = 45 ml

In prepared solution,

V₂ = 15 ml

Concentration,

C₁ = ?

C₂ = 3.0 M

As we know,

⇒
`V_1C_1=V_2C_2`

or,

⇒
`C_1=(V_2C_2)/(V_1)`

On substituting the values, we get

⇒
`=(15* 3)/(45)`

⇒
`=(45)/(45)`

⇒
`=1 \ M`