Question

What is the mass of sulfuric acid, h2so4, that is contained in 2.0L of a 5.85 M solution ?

A- 1147.44 grams
B- 0.12 grams
C- 11.7 grams
D- 98.07 grams

Answer 1

A. 1147.44 grams

Step-by-step explanation:

Multiply volume by molarity to get the moles of solution.

5.85 M = mol/2.0 L

mol = (5.85 M)(2.0 L)

mol = 11.7

There is 11.7 moles of H2SO4.

Convert to grams with molar mass.

11.7 mol H2SO4 x (98.076 g/1 mol) = 1147.49 g

Closest answer is A, 1147.44 g.