Question

What is an
equation of the line that passes through the points (6, -7) and (4, -6)?

Answer 1

x+2y+8=0

Explanation:

The equation of straight line passing through the given points

(x 1,y1) = (6,-7)

(X2,y2)=(4,-6)

is given by following formula

y-y1={(y2-y1)/(x2-x1)}×(x-x1)

y+7={(-6+7)/(4-6)}×(x-6)

y+7={1/(-2)}×(x-6)

-2y-14=x-6

0=x+2y-6+14

x+2y+8=0

This is the required equation for line passing through (6,-7) and (4,-6)

Answer 2

The equation is y =
`(-1)/(2)` * x - 4

How to find the slope:
`(Rise)/(Run)` =
`(-1)/(2)` (since the rise is going down by 1 unit and the run is 2 units to the right)

How to find the y-intercept: You draw a line that go through the 2 points until it touches the y-axis and that is your y-intercept