Question

A bulb plugged into a 110V wall socket has a resistance of 200 Ω. Calculate the how many seconds it will take to pass 2500 C of charge. USE GRASP methoth PLSSSS

Answer 1

The right solution is "4545.45 seconds".

Step-by-step explanation:

The given values are:

Charge,

C = 2500 C

Resistance,

R = 200 Ω

Bulb plugged into,

V = 110 V

As we know,

⇒
`I=(V)/(R)`

On substituting the values, we get

⇒
`=(110)/(200)`

⇒
`=0.55 \ A`

Now,

⇒
`Q=I* t`

or,

⇒
`t=(Q)/(I)`

On substituting the values, we get

⇒
`=(2500)/(0.55)`

⇒
`=4545.45 \ seconds`