Question

a rocket burns propellant at a rate of dm/dt = 3.0 kg/s, ejecting gases with a speed of 8000 m/s relative to the rocket. Find the magnitude of the thrust.

Answer 1

Answer: 24 kN

Step-by-step explanation:

Given

The rocket burns propellant at the rate of

`(dm)/(dt)=3\ kg/s`

Relative ejection of gases
`v=8000\ m/s`

The magnitude of thrust force is given by

`F_t=v(dm)/(dt)\\\\F_t=8000* 3=24,000\ N\ or\ 24\ kN`