Question

The sum of two numbers is 48. The second number is twice the first

Write and solve a system of equations to find the numbers.

Answer 1

The equations are

X + Y = 48 ----Eq (1)

Y = 2 X -----Eq (2)

Solution of the equations and the two number are

X = 16, Y = 32

Explanation:

Let the two numbers be X and Y

Given -

The sum of two numbers is 48.

Thus, X + Y = 48 ----Eq (1)

The second number is twice the first

Thus, Y = 2 X -----Eq (2)

Substituting the value of Y in equation (1), we get -

X + 2X = 48

3 X = 48

X = 16

Y = 2 X = 32