Question

A wheel with radius 1 foot makes 1 revolution in 4 seconds. What is the linear velocity, in feet per second, of a point on the edge of the wheel? 4π 8π

Answer 1

pi/2

B

Explanation:

Got it right on EG

Answer 2

`v=(\pi)/(2)\ ft/s`

Explanation:

Given that,

A wheel with radius 1 foot makes 1 revolution in 4 seconds

We need to find the linera velocity of a point on the edge of the wheel. We know that, the linear velcity is given by :

`v=r\omega`

Where

`\omega` is angular velcocity,
`\omega=2\pi\ rad`

`\omega=(1)/(4)* 2\pi\\\\=0.5\pi\ rad/s`

So

`v=1* 0.5\pi\\\\v=(\pi)/(2)\ ft/s`

So, the linear velocity of the wheel is equal to
`(\pi)/(2)\ ft/s`.