Answer:
65.1 grams
Step-by-step explanation:
The percentage of impurities in the contaminated CaCl₂ sample is:
- % of NaCl + % of sand = 7%
Meaning that the purity of the sample is (100 - 7) 93%.
Now we calculate the mass of pure CaCl₂ in the contaminated sample:
Thus the answer is 65.1 grams, as that amount is how much CaCl₂ is in the sample and it would be impossible to obtain more than that.