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In order to implement the classic DoS flood attack, the attacker must generate a sufficiently large volume of packets to exceed the capacity of the link to the target organization. Consider an attack using ICMP echo request (ping) packets that are 500 bytes in size (ignoring framing overhead). How many of these packets per second must the attacker send to flood a target organization using a 0.5-Mbps link

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Answer:

131 packets

Step-by-step explanation:

Given

W (link ) =0.5 M bits, and Ping packets ( P ) = 500bytes

To flood a target organization that has a bandwidth of W bits using a packet Mbits, you will require a W / P packet

P ( required ) = 500 * 8 = 4000 bits

therefore the W /P packet is calculated as

= 0.5 M bits / 4000 bits

given that : 1 M bits = 1,048,576 bits

0.5 M bits / 4000 bits= 131.07

hence approximately 131 packets/ sec is required to flood the target organization

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