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1 vote
8.

Find the area of the shaded region.


A. 5x2 – 11x + 16

B. 5x2 + 7x – 26

C. 5x2 + 11x – 12

D. 5x2 + 7x – 20

8. Find the area of the shaded region. A. 5x2 – 11x + 16 B. 5x2 + 7x – 26 C. 5x2 + 11x-example-1

2 Answers

3 votes

Answer:

B. 5x2 + 7x – 26

Step-by-step explanation: keeping in mind that the area of a rectangle is simply width * length, if we get the area of the larger rectangle, and then subtract the area of the smaller rectangle, we're in effect making a hole in the larger rectangle's area and thus what's leftover is the shaded area.

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Answer:

Area = 5x^2 +7x -26

Step-by-step explanation:

The area of the shaded region can be found if you substruct the small rectangle from the big one. The area of any rectangle is calculated if you multiply width and height.

In other words:

A_small = (x-3)(x-6) = x^2-9x +18

A_big = (2x+2)(3x-4) = 6x^2 -2x -8

A_big - A_small = (6x^2 -2x -8) - (x^2-9x +18)

= 6x^2 -2x -8 - x^2 + 9x -18

= 5x^2 +7x -26

8. Find the area of the shaded region. A. 5x2 – 11x + 16 B. 5x2 + 7x – 26 C. 5x2 + 11x-example-1
User Zoltan Varadi
by
4.6k points
2 votes

Area of the shaded region = area of big square minus area of little square.

Here is the set up:

Let A_s = area of shaded region.

A_s = (2x + 2)(3x - 4) - [(x - 3)(x - 6)]

Take it from here.

User Marti Nito
by
4.7k points