Question

[Example 1]

Write an equation of the line passing through the
point (-3,10) that has a slope of5/3

Answer 1

`y=(5)/(3)x+5`

Explanation:

first, m (gradient) = 5/3, Point(-3,10) = (x1, y1)

substitute values into point-gradient formula:

`y-y_(1) =m(x-x_(1))\\y-(10)=(5)/(3)(x-(3))\\`

simplify...

`y-10=(5)/(3)x-5\\ y=(5)/(3)x+5`

Therefore

`y=(5)/(3)x+5` is the answer