Please? Anyone, help me with this? Thank you!!

asked Mar 23, 2023 152k views

22 votes

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$\\ \rm\Rrightarrow (x^(2/3)y^(1/2))^(-6)=x^(2(-2))y^(-3)=x^(-4)y^(-3)=(1)/(x^4y^3)$

$\\ \rm\Rrightarrow 4^(3/4)4^(-1/2)=4^(3/4-1/2)=4^(3-2/4)=4^(1/4)=\sqrt[4]{4}=√(2)$

$\\ \rm\Rrightarrow ((6x^6y^8)/(12^(16)))^(1/4)$

$\\ \rm\Rrightarrow (6^(1/4)x^(3/2)y^(2))/(12^4)$

Robb answered Mar 29, 2023

by Robb

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