Answer:
q = mC∆T
q = heat = ?
m = mass = 6.30 g
C = specific heat = 0.385 J/g/deg
∆T = change in temperature = 32-20 = 12º
q = ((6.30 g)(0.385 J/g/deg)(12 deg) = 29.1 J (to 3 significant figures)
Step-by-step explanation:
3.3m questions
4.2m answers