Question

The length of a rectangle is 3ft less than double the width, and the area of the rectangle is 14ft^2 find the dimensions of rectangle.

Answer 1

Answer:
`4* 3.5\ ft^2`

Explanation:

Given

area of the rectangle is
`A=14\ ft^2`

Suppose width is given by w

So, length is
`l=2w-3`

The area of a rectangle is
`A=l* w`

putting values

`\Rightarrow A=(2w-3)w\\\Rightarrow 14=2w^2-3w\\\Rightarrow 2w^2-3w-14=0\\\Rightarrow 2w^2-7w+4w-14=0\\\Rightarrow w(2w-7)+2(2w-7)=0\\\Rightarrow (2w-7)(w+2)=0\\\\\Rightarrow w=(7)/(2)\ ft`

length is
`l=4\ ft`