Question

Calculate the molarity of each aqueous solution with the given amount of Nacl58.44 and final volume. A .3.30 in 0.340L,6.00mol in 550ml,0.0160mol in 9.00ml

Answer 1

For A: The molarity is the solution 9.706 M

For B: The molarity of the solution is 10.91 M.

For C: The molarity of the solution is 1.78 M.

Step-by-step explanation:

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L.

The formula used to calculate molarity:

`\text{Molarity of solution}=\frac{\text{Number of moles of solute}}{\text{Volume of solution (L)}}` ......(1)

For A:

Number of moles = 3.30 moles

Volume of solution = 0.340 L

Plugging values in equation 1:

`\text{Molarity of solution}=(3.30 mol)/(0.340 L)=9.706 mol/L`

For B:

Number of moles = 6.00 moles

Volume of solution = 550 mL = 0.550 L (Conversion factor: 1 L = 1000 mL)

Plugging values in equation 1:

`\text{Molarity of solution}=(6.00 mol)/(0.550 L)=10.91 mol/L`

For C:

Number of moles = 0.0160 moles

Volume of solution = 9.00 mL = 0.009 L

Plugging values in equation 1:

`\text{Molarity of solution}=(0.0160 mol)/(0.009 L)=1.78 mol/L`