Answer:
2x^3−7x^2+16x−15
Explanation:
(2x−3)(x^2−2x+5)
=(2x+−3)(x^2+−2x+5)
=(2x)(x^2)+(2x)(−2x)+(2x)(5)+(−3)(x^2)+(−3)(−2x)+(−3)(5)
=2x^3−4x^2+10x−3x^2+6x−15
=2x3−7x2+16x−15
2x³ -7x² +16x -15
You distribute the (2x-3) onto the other trinomial and then combine the like-terms.
(2x-3)(x²-2x+5)
2x³ -4x² + 10x -3x² +6x -15
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