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Reduce: [(p → q)] ∧ q] ∧ [(q → p) ∧ p]

Reduce: [(p → q)] ∧ q] ∧ [(q → p) ∧ p]
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Reduce: [(p → q)] ∧ q] ∧ [(q → p) ∧ p]

User Riaz Hasan
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what? bro I am confused is this a question?

User Randomcontrol
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