Question

How much energy is required to raise the temperature of 10.6 grams of gaseous neon from

20.0 °C to 37.9 °C ?

Answer 1

Approximately
`1.95 * 10^(2)\; \rm J`.

Step-by-step explanation:

Look up the specific heat of gaseous neon:

`c = 1.03 \; \rm J \cdot g^(-1) \cdot K^(-1)`.

Calculate the required temperature change:

`\Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K`.

Let
`m` denote the mass of a sample of specific heat
`C`. Energy required to raise the temperature of this sample by
`\Delta T`:

`Q = c \cdot m \cdot \Delta T`.

For the neon gas in this question:

• 
  `c = 1.03\; \rm J \cdot g^(-1)\cdot K^(-1)`.
• 
  `m = 10.6\; \rm g`.
• 
  `\Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K`.

Calculate the energy associated with this temperature change:

`\begin{aligned}Q &= c \cdot m \cdot \Delta T \\ &= 1.03\; \rm J \cdot g^(-1)\cdot K^(-1) * 10.6\; \rm g * 17.9\; \rm K \\ &\approx 1.95 * 10^(2)\; \rm J\end{aligned}`.