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The 2nd term of an exponential sequence is 9 while the 4th term is 81.find the common ratio,the first term and the sum of the first five terms of the sequence

User CAA
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Answer:

second term: 9

4th term:81


(3rd \: term)^(2) = 9 * 81

=729


√(729) = 27

3rd term=27


{9}^(2) = a1x27 \\ 81 = 27a1

a1=3 the first term


81 = 3 * {q}^(3)


{q}^(3) = 27

q=3


s = 3x \frac{1 - {3}^(5) }{1 - 3} = 364.5

User Ines Tlili
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