189k views
0 votes
What is a linear function in the form y=mx+b for the line passing through (2, -4) with y-intercept 2?

What is a linear function in the form y=mx+b for the line passing through (2, -4) with-example-1

1 Answer

5 votes

Answer:

A linear function in the form y = m·x + b for the line passing through the point (2, -4) with y-intercept 2 is;

y = -3·x + 2

Explanation:

From the question, it is required to find the a linear equation passing through the point (2, - 4) with a y-intercept 2 in the form y = m·x + c

Given that the y-intercept is the point at which the line cuts the y-axis, we have, x = 0

Therefore, we have the point on the line representing the y-intercept is (0, 2)

Therefore, the slope of the graph is given as follows;


Slope, \, m =(y_(2)-y_(1))/(x_(2)-x_(1))

Therefore, we have;


Slope, \, m =(2-(-4))/(0-2) = (6)/(-2) = -3

The equation of the graph in point and slope is given as follows;

y - 2 = -3 × (x - 0) = -3 × x

Therefore, the equation of the line in the form y = m·x + c is given as follows;

y - 2 + 2 = -3 × x + 2

∴ y = -3·x + 2

The equation of the line in the form y = m·x + c is y = -3·x + 2.

User Wawa Loo
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories