Evaluate y = [X + 1] at x = 3.001?

asked Dec 22, 2022 55.5k views

1 vote

6.3k points

Please log in or register to add a comment.

6 votes

Answer: 4

Explanation:

Given

y=[x+1]

where,
[ ]= Greatest integer function

Put
x=3.001

$\Rightarrow y=[3.001+1]=[4.001]\\\Rightarrow y=[4+0.001]=4$

Thus, the value of y is 4

MalphasWats answered Dec 27, 2022

5.9k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

6.2m questions

8.2m answers