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Choose the step in which the first error occurs. Then evaluate the expression to find the correct answer.

3−(5−32+4)+6^2·(−2)

3−0+6^2·(−2) step 1
3−0+36·(−2) step 2
3−0+(−72) step 3
75 step 4

The first error occurs in step____ .
The value of 3−(5−32+4)+62·(−2) is ____.

Choose the step in which the first error occurs. Then evaluate the expression to find-example-1
User Rickert
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1 Answer

7 votes

Answer:

The first error occurs in Step 3

The value of the equation is -69

Explanation:

The error is that 3-0+(-72) is actually supposed to be 3-0-72 because once you multiply the positive 36 and the negative 2, the equation automatically becomes negative.

User Igor
by
8.6k points
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