Question

a particle moves along of the x_axis according to the equation X=2t+3t^2, whare x is in m and t is in second. calcualt the instantaneous velocity and the instantaneous acceleration in t=3s​

Answer 1

Instantaneous velocity
`= 20` meter per second

Instantaneous acceleration
`= 6` meter per second square

Step-by-step explanation:

Given equation of distance X =
`2t+3t^2`

Instantaneous velocity
`= (dX)/(dt)`
`= 2 + 6 t`

Substituting the value of t = 3 seconds, we get -

`(dX)/(dt) = 2 + 6*3 = 20` meter per second

Instantaneous acceleration
`= (d^2X)/(dt^2)`
`= 6` meter per second square