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a car is traveling at 20m/s along a road. a child runs out into the road 50 m ahead and the car driver steps on the break. what must the car's decelaration be if the car is to stop just before it reaches the child.

1 Answer

2 votes

Answer:

4 m/s²

Step-by-step explanation:


v {}^(2) = {u}^(2) + 2as \\ 0 {}^(2) = {20}^(2) + 2a(50) \\ a = - 4ms {}^( - 2)

Therefore, deceleration = 4 m/s²

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