80.0k views
0 votes
A bag of color tiles contains 2 red, 1 blue, 1 green, and 4 yellow. Sean reaches in and draws one

tile without replacing it. He then draws a second tile and a third tile without replacing them. Which
of the following combinations is a possible draw?
F:red,blue,blue G:red,green,green H:yellow,blue,green J:blue,blue,green

2 Answers

2 votes

Answer:

H: yellow, blue, green

Explanation:

F: red, blue, blue = cannot be true as there is 1 blue tile in bag and it cannot be drawn twice without replacing first draw.

G: red, green, green = cannot be true because 1 original green tile in bag cannot be drawn twice

J: blue,blue, green = cannot be true for same reason; 1 original blue tile cannot be drawn twice without replacement.

User Oliverdejohnson
by
7.9k points
3 votes

Answer:

H

Explanation:

Since there is 4 yellows, 1 green, and 1 blue, there is no way you could draw 2 blues or 2 greens. Therefore, F, G, and J are immediately eliminated. The only answer left is H, and it makes sense. H is the answer.

User Doren
by
8.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories