Question

helppppp meeeeee the sum of the squares of three consecutive integer numbers is 1454. Find the numbers. but i found 21 22 and 23. you need to find the other set plzzz​

Answer 1

Explanation:

A=x

B=x+1

C=x+2

`{x}^(2) + {(x + 1)}^(2) + {(x + 2)}^(2) = 1454 \\ {x}^(2) + {x}^(2) + 2x + 1 + {x}^(2) + 4x + 4 = 1454 \\ 3{x}^(2) + 6x + 5 - 1454 = 0 \\ 3 {x}^(2) + 6x - 1449 = 0 \\ {x}^(2) + 2x - 483 = 0`

I'm sorry but I can't use the calculator, I hope this helps you anyway.

Answer 2

The two sets would be 21,22,23 and -21, -22, and -23

Explanation:

This is because a negative number squared would be positive.

So -21^2+-22^2+-23^2 would equal the same as 21^2+22^2+23^2 which would be 1454.