Question

Kayla bought a necklace for $15. She also bought some bangle bracelets for $3 each. Kayla spent no more than $30 for the bracelets and the necklace. Which inequality can be used to find b, the number of bangle bracelets that Kayla could have bought?

Answer 1

15 + 3b ≤ 30

Kayla can buy no more than 5 bangle bracelets

Explanation:

Let b = number of bangle bracelets

If Kayla bought a necklace for $15, some bangle bracelets for $3 each, and spent no more than $30:

15 + 3b ≤ 30

To solve:

15 + 3b ≤ 30

Subtract 15 from both sides:

⇒ 3b ≤ 15

Divide both sides by 3:

⇒ b ≤ 5

So Kayla can buy no more than 5 bangle bracelets

Answer 2

she bought 5 or less than 5 bracelets .

Explanation:

Let bracelets be b,

cost of total bracelets: 3b

inequality:

• 3b + 15 ≤ 30

• 3b ≤ 30 - 15

• 3b ≤ 15

• b ≤ 15/3

• b ≤ 5