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Simplify x^2-9 over x^2-3x

User Grep
by
8.9k points

2 Answers

5 votes

Answer:


x^(2) -3x-(9)/(x^(2) )

Explanation:


x^(2) -9 ÷
x^(2) -3x

To add or subtract expressions, expand them to make their denominators the same. Multiply
x^(2) -3x times
(x^(2) )/(x^(2) )

-


((x^(2) -3x)x^(2) )/(x^(2) ) - (9)/(x^(2) )

Since
((x^(2) -3x)x^(2) )/(x^(2) ) and
(9)/(x^(2) ) have the same denominator, subtract them by subtracting their numerators.

-


((x^(2) -3x)x^(2) -9)/(x^(2) )

Do the multiplications in
(x^(2) -3x)x^(2) -9

-


(x^(4)-3x^(3)-9 )/(x^(2) )

User Kerry G
by
8.7k points
9 votes

Answer:


(x+3)/(x) or x+3/x

Explanation:

Using D.O.T.S (difference of two squares) formula :


a^(2) -b^(2) = (a+b)(a-b)


x^(2) -9= (x+3)(x-3)

Factorise the second bit:


x^(2) -3x = x(x-3)

Now write out this fraction:


((x+3)(x-3))/(x(x-3))

Now we can cancel out repeated terms (x-3):


((x+3))/(x)
This is our final answer:


(x+3)/(x)

User Jhamman
by
7.7k points

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