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In ΔCDE, the measure of ∠E=90°, the measure of ∠C=43°, and CD = 95 feet. Find the length of EC to the nearest tenth of a foot.
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In ΔCDE, the measure of ∠E=90°, the measure of ∠C=43°, and CD = 95 feet. Find the length of EC to the nearest tenth of a foot.

In ΔCDE, the measure of ∠E=90°, the measure of ∠C=43°, and CD = 95 feet. Find the-example-1
User Phil Blackburn
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2 Answers

6 votes
69.5 is the answer I’m sure
User Shorn Jacob
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4.1k points
1 vote

9514 1404 393

Answer:

69.5

Explanation:

The useful trig relation in this case is ...

Cos = Adjacent/Hypotenuse

cos(43°) = x/95

x = 95×cos(43°) ≈ 69.5 . . . . feet

User Deiveegaraja Andaver
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3.6k points
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