Question

In ΔBCD, the measure of ∠D=90°, the measure of ∠B=22°, and DB = 44 feet. Find the length of BC to the nearest tenth of a foot.

Answer 1

Answer: 47.5 ft

Explanation:

since this is a right triangle, you can use trig to solve for x:

cos 22° =
`(44)/(x)` (cos = adjacent/hypotenuse)

x * cos 22° = 44

x =
`(44)/(cos 22)` (plug into calc)

x = 47.5 ft