Question

A tiger leaps horizontally from a 6.5 m tall rock with a speed of 3.5 ms. How many seconds will it take for her to land?

Answer 1

Answer: 1.15 s

Step-by-step explanation:

Given

Height of rock h=6.5 m

The horizontal speed of tiger u=3.5 m/s

In the vertical direction, there is no initial speed

Using the equation of motion

`\Rightarrow h=ut+(1)/(2)at^2\\\\\Rightarrow 6.5=0+(1)/(2)* 9.8* t^2\\\\\Rightarrow t=\sqrt{(13)/(9.8)}=1.15\ s`

Time taken is 1.15 s