Question

A 2200 kg car traveling at 25 m / s [S] stops in 10 s.

Determine:
the acceleration of the car;
the net force required to produce this acceleration.

Answer 1

`-2.5\ \text{m/s}^2`

`-5500\ \text{N}`

Step-by-step explanation:

m = Mass of car = 2200 kg

t = Time = 10 s

v = Final velocity = 0

u = Initial velocity = 25 m/s

a = Acceleration

From the kinematic equations of linear motion we have

`v=u+at\\\Rightarrow a=(v-u)/(t)\\\Rightarrow a=(0-25)/(10)\\\Rightarrow a=-2.5\ \text{m/s}^2`

Acceleration of the car is
`-2.5\ \text{m/s}^2`

Force is given by

`F=ma\\\Rightarrow F=2200* (-2.5)\\\Rightarrow F=-5500\ \text{N}`

Net force required to produce the acceleration is
`-5500\ \text{N}`.