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Find the area of the triangle whose vertices are (0,0), (3,0)& (0,2)??? please help :)​

User Aerique
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1 Answer

1 vote

Answer:

3 units^2

Explanation:

Note that two vertices of this triangle are on the same line, the y-axis, since the x-coordinates are the same (0). The distance between them is (2 - 0), or 2. This represents the height of the triangle, since we're measuring straight up from the x-axis to the vertex (0, 2).

The one remaining vertex, (3, 0) lies on the x-axis. The distance from the origin to this vertex is 3, which represents the length of the base of the triangle (3).

Thus, the area of the triangle is A = (1/2)(base)(height), or

A = (1/2)(3)(2) = 3 units^2

User Jhoff
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