148k views
4 votes
Show that a square b square c square are in AP if and only if 1/b + c ,1/c+ a,1/ a + b are in AP​

User Detect
by
8.6k points

1 Answer

3 votes

In AP form 2nd term - 1st term = 3rd term - 2nd term

b²-a² = c²-b²

b²+b² = c²+a²

2b² = c²+a²

Add 2ab+2ac+2bc on both sides

2b²+2ab+2ac+2bc = a²+c²+ac+ac+bc+bc+ab+ab

2b²+2ab+2ac+2bc = ac+bc+a²+ab+bc+c²+ab+ac

2b²+2ab+2ca+2cb = ca+cb+a²+ab+cb+c²+ab+ac

2(ba+b²+ca+cb) = (ca+cb+a²+ab) + (cb+c²+ab+ac)

2((ba+b²)+(ca+cb)) = ((ca+cb)+(a²+ab)) + ((cb+c²)+(ab+ac))

2(b(a+b)+c(a+b)) = (c(a+b)+a(a+b)) + (c(b+c)+a(b+c))

2(b+c)(a+b) = (c+a)(a+b) + (c+a)(b+c)

Divide whole by (a+b)(b+c)(c+a)

2/c+a = 1/b+c + 1/a+b

1/c+a + 1/c+a = 1/b+c + 1/a+b

1/c+a - 1/b+c = 1/a+b - 1/c+a

2nd term - 1st term = 3rd term - 2nd term

Thus 1/b+c, 1/c+a, 1/a+b are in AP.

HOPE IT HELPS !!!

THANK YOU !!!

User NBajanca
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories