Answer:
LM = 22
Explanation:
If a tangent segment and a secant segment are drawn from an exterior point to a circle, then the square of the measure of the tangent segment is equal to the product of the measures of the external secant segment and the secant segment.
So for this circle,
- point of intersection = M
- tangent segment = LM
- external secant segment = NM
- secant segment = OM
So LM² = NM · OM
Given:
LM² = 11 · 44 = 484
⇒ LM = √484 = 22