Answer:
Work done is 882000joule.
power is 29400watt.
Step-by-step explanation:
given,
Mass(m)=500kg
Acceleration due to gravity(g)=9.8m/s²
Height(h)=6m
Time taken(t)=30s
Workdone=?
Power=?
now,
workdone=force*displaxement
= m*g*h
=500*9.8*6
=8,82,000joule
so, the work done by the man is 8,82,000joule.
then,
power=workdone/time taken
=8,82,000/30
=29,400watt
so, the required power to lift a load is 29,400watt.