Note: The third term of the sequence should be
instead of
, otherwise the sequence has no common ratio.
Given:
The given sequence is
![24,18,(27)/(2),(81)/(8)](https://img.qammunity.org/2022/formulas/mathematics/high-school/8x2l448m2nwrwz7bdo50rf8c30s05p7mds.png)
To find:
The common ratio of the given sequence.
Solution:
The quotient of each pair of consecutive terms are:
![(18)/(24)=(3)/(4)](https://img.qammunity.org/2022/formulas/mathematics/high-school/g5of81438gg0ew92c0ab6hv581muo484gw.png)
Similarly,
![((27)/(2))/(18)=(27)/(36)](https://img.qammunity.org/2022/formulas/mathematics/high-school/isvw8je58oc0ax30j97ik23j0icj6a0i9e.png)
![((27)/(2))/(18)=(3)/(4)](https://img.qammunity.org/2022/formulas/mathematics/high-school/5mx0dd33d7m45r5m9m8aj7qh8dhytywdis.png)
And,
![((81)/(8))/((27)/(2))=(81)/(8)* (2)/(27)](https://img.qammunity.org/2022/formulas/mathematics/high-school/624t1qp05izt9rsc2q1cu28v0wruarua6c.png)
![((81)/(8))/((27)/(2))=(3)/(4)](https://img.qammunity.org/2022/formulas/mathematics/high-school/v36cjxj9y3munepz5dfrb1d1e9pei8ec6s.png)
Therefore, the common ratio of the given sequence is
or 0.75.