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Question involving the equations for Hardy Weinberg equilibrium (A^2+2Aa+a^2=1, A+a=1)

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Question involving the equations for Hardy Weinberg equilibrium (A^2+2Aa+a^2=1, A-example-1

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Answer:

Frequency of dominant allele is 0.9029

Step-by-step explanation:

Total number of organisms = 12,845

Number of organisms representing dominant trait = 11,596. These organisms might have heterozygotes with one dominant allele and one recessive allele.

Hence, Number of organisms with recessive alleles = 12845 – 11596 = 1249

Frequency of recessive allele (q) = 1249/12845 = 0.0971

Frequency of dominant allele (p) = 1- q = 1- 0.0971 = 0.9029

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