56.3k views
2 votes
Can someone please help!

find the minimum value of the function f(x)=0.2x^2-x+5.2
to the nearest hundredth.

User Lrsjng
by
7.4k points

1 Answer

4 votes

Answer:

min f(x) = 3.95 (for x= 2.5)

Explanation:

vertex (x) = 1/0,4 = 2,5

vertex (y) = 0.2(2.5)^2-2.5+5.2 = 3.95

User Voam
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories