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Find the area of a trapezium whose parallel sides are 34 cm and 40cm and the distance between them is 20 cm​

User Nonozor
by
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1 Answer

12 votes

Answer:

area of trapezium: 740 cm²

Explanation:


\sf {Area \ of \ trapezium = (1)/(2)* (base \ 1 \ + base \ 2) \ * height }

Given here:

  • base 1: 34 cm
  • base 2: 40 cm
  • height: 20 cm

using the formula:


\sf {Area \ of \ trapezium = (1)/(2)* (base \ 1 \ + base \ 2) \ * height }

solve:


\sf {(1)/(2)* (34 \ + 40) \ * 20}


\sf {(1)/(2)* (74) \ * 20}


\sf 74 * 10


\sf 740

User Joost Vunderink
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4.6k points