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Two girls are standing 100 feet apart they both see a beautiful seagull in the air between them the angles of elevation from the girls to the bird are 20 degrees and 45 degrees respectively how high up is the seagull

1 Answer

2 votes

Answer:


26.68\ \text{feet}

Explanation:

a = 100 feet


\angle B=20^(\circ)


\angle C=45^(\circ)


\angle A=180-(20+45)=115^(\circ)

From sine rule we have


(\sin B)/(b)=(\sin A)/(a)\\\Rightarrow b=(\sin B)/(\sin A)a\\\Rightarrow b=(\sin 20^(\circ))/(\sin 115^(\circ))* 100\\\Rightarrow b=37.73\ \text{feet}


\sin C=(h)/(b)\\\Rightarrow h=b\sin C\\\Rightarrow h=37.73* \sin 45^(\circ)\\\Rightarrow h=26.68\ \text{feet}

The is seagull is
26.68\ \text{feet} above the ground.

Two girls are standing 100 feet apart they both see a beautiful seagull in the air-example-1
User Ankit Aman
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