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21.evaluate 22.find dy/dx​

21.evaluate 22.find dy/dx​-example-1

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Answer:

y' = -y/x

Explanation:

It looks like you have ...

e^z -z = 0 . . . . . where z = xy

Differentiating with respect to x gives ...

z'·e^z -z' = 0

z'(e^z -1) = 0

The zero-product rule tells you this is true for e^z = 1, which is not useful for finding y', and for z' = 0, which is.

z = xy

z' = y +xy' = 0

y' = -y/x

_____

Additional comment

There appear to be no real values of x and y that will make your equation true.

User Morgan Courbet
by
8.6k points

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