Answer:
2C₄H₁₀ + 13O₂---> 8CO₂ + 10H₂O
Step-by-step explanation:
This is a type of combustion reaction which produces carbon dioxide and water:
C₄H₁₀ + O₂---> CO₂ + H₂O
1) There are 10 hydrogens on the left and 2 hydrogens on the right so put a 5 in front of the H₂O because 5 × 2 = 10
now we have: C₄H₁₀ + O₂---> CO₂ + 5H₂O
2) C₄H₁₀ + O₂---> CO₂ + 5H₂O
There are 4 carbons on the left and 1 carbon on the right, so put a 4 in front of CO₂, now we have:
C₄H₁₀ + O₂---> 4CO₂ + 5H₂O
3) C₄H₁₀ + O₂---> 4CO₂ + 5H₂O
There are 2 oxygens on the left and 13 oxygens on the right (In 4CO₂ 4 × 2 = 8 oxygens and in 5H₂O there are 5 oxygens, 8 + 5 = 13 oxygens). To balance this put 6.5 in front of the O₂ because 6.5 × 2 = 13
now we have:
C₄H₁₀ + 6.5O₂---> 4CO₂ + 5H₂O
we cannot have half of a molecule, so multiply the whole equation by 2 which gives us:
2C₄H₁₀ + 13O₂---> 8CO₂ + 10H₂O