Question

If 95 grams of Iron are needed to react with sulfur, how many grams of sulfur are involved in this reaction?

2 Fe + 3 S à Fe2S3

Answer 1

You need a balanced equation.

2Fe(s) + 3S(s) ==> Fe2S3(s) ... balanced equation

Reactants are solid iron and solid sulfur

Product is iron(III) sulfide

A. 1.42 moles Fe x 3 moles S/2 moles Fe = 2.13 moles sulfur

B. 2.75 moles S x 2 moles Fe/3 moles S = 1.83 moles iron