Given:
The pair of similar triangles.
Base of smaller triangle = 10 in
Base of larger triangle = 14 in
To find:
The ratio of the perimeters and the ratio of the areas.
Solution:
Ratio of perimeter of similar triangles is equal to the ratio of their corresponding sides.



The ratio of area of similar triangles is equal to the ratio of squares of their corresponding sides.




Therefore, the ratio of the perimeters is 5:7 and the ratio of the areas 25:49.