Answer:
Centre = (2, -3)
radius = 5units
Explanation:
The standard form of a circle is expressed as;
x²+y²+2gx+2fy+c = 0
Centre = (-g, -f)
radius r = √g²+f²-c
Given the equation;
x²+y²-4x+6y-12 = 0
Compare
2gx = -4x
2g = -4
g = -2
Similarly;
2fy = 6y
2f = 6
f = 3
Centre = (-(-2), -3)
Centre = (2, -3)
Radius = r = √(-2)²+3²+12
r = √4+9+12
r = √25
r = 5 units